Water Supply Engineering Solved Problems Pdf -

Reynolds Re = V×D/ν = 1.99×0.4 / 1e-6 = 796,000 (turbulent) Relative roughness = ε/D = 0.045/400 = 0.0001125 From Moody chart: f ≈ 0.014 Head loss h_f = f × (L/D) × (V²/(2g)) = 0.014 × (800/0.4) × (1.99²/(2×9.81)) = 0.014 × 2000 × (3.96/19.62) = 0.014 × 2000 × 0.202 = 5.66 m

Q_avg = 75,000 × 200 = 15,000,000 L/day = 15,000 m³/day (173.6 L/s) water supply engineering solved problems pdf

Hydraulic power P_h = ρ × g × Q × H = 1000 × 9.81 × 0.05 × 60.46 = 1000 × 9.81 × 3.023 = 29,660 W = 29.66 kW Reynolds Re = V×D/ν = 1

Average increase per decade = [(55-45)+(68-55)+(84-68)] / 3 = (10+13+16)/3 = 13,000 per decade P2030 = P2010 + 2 × 13,000 = 84,000 + 26,000 = 110,000 000 × 200 = 15

Q_max daily = 1.8 × 15,000 = 27,000 m³/day (312.5 L/s)