Work: Fizika 7 Razred Zadaci I Rješenja

[ p = \fracFA = \frac500 , \textN0.25 , \textm^2 = 2000 , \textPa ] Problem 8 Calculate the water pressure at 2 m depth. (( \rho_\textwater = 1000 , \textkg/m^3, g = 10 , \textN/kg ))

[ F_g = m \cdot g = 5 , \textkg \times 10 , \textN/kg = 50 , \textN ] Problem 4 A force of 20 N acts on a 4 kg object. What is its acceleration? fizika 7 razred zadaci i rješenja

[ s = v \cdot t = 5 , \textm/s \times 20 , \texts = 100 , \textm ] 2. Force (Sila) Key formula: ( F = m \cdot a ) (Newton’s second law) Unit: Newton (N) Weight: ( F_g = m \cdot g ) (( g \approx 9.81 , \textN/kg ), often taken as ( 10 , \textN/kg ) in 7th grade) Problem 3 What is the weight of a 5 kg object? (Use ( g = 10 , \textN/kg )) [ p = \fracFA = \frac500 , \textN0

[ \rho = \fracmV = \frac240 , \textg300 , \textcm^3 = 0.8 , \textg/cm^3 ] In kg/m³: [ 0.8 , \textg/cm^3 = 0.8 \times 1000 = 800 , \textkg/m^3 ] Problem 6 Iron has density 7800 kg/m³. What is the mass of 0.05 m³ of iron? [ s = v \cdot t = 5

[ a = \fracFm = \frac20 , \textN4 , \textkg = 5 , \textm/s^2 ] 3. Density (Gustoća) Key formula: ( \rho = \fracmV ) Unit: ( \textkg/m^3 ) or ( \textg/cm^3 ) Conversion: ( 1 , \textg/cm^3 = 1000 , \textkg/m^3 ) Problem 5 A wooden block has mass 240 g and volume 300 cm³. Calculate density in g/cm³ and kg/m³.